Not to disappoint I shall at least make one new post during my winter break. However, do not look for this to be a recap of how things went. If I could I would rather just forget that these three weeks or so ever happened. On the bright side I did however, manage to get some productive things done. I finished reading the chapter on continuity and have almost finished reading the chapter on differentiation. While working through the continuity exercised I ran into one that was particularly interesting problem. Before going any further I would like to mention that I had to ask for help in finding this solution.
Theorem:
Every real-valued convex function is continuous.
A real-valued function
defined in is said to be convex ifTheorem:
Every real-valued convex function is continuous.
A real-valued function
whenever and .
Lemma: If is continuous in (a,b) and if then
Proof of lemma: This is not to difficult to prove so I shall just give the major idea and leave the rest to the reader. Let . Obviously , so use this new way to express and the rest follows with ease.
Proof of theorem:
First we choose a point
and a neighborhood of such that . Now using the lemma we have that, for .
Now from this we see that there is a positive number such that . Let . Thus if we have that .
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