This is the solution for problem #1 in my previous post.
Let , since
is a Cauchy sequence there exist an
such that if
if
Similarly since a subsequence converges to
we have that
when
. Now let
be the larger of
and
.
Now .
Here is the solution for #2 in my previous post (this one took a little longer for me to think of).
Let be a sequence in
such that
. Now from properties of
we have that
for all
Now let
, and since
we have that
for
large enough. So
since
is complete. Additionally,
is a limit point of each
, so
.
Saturday, August 02, 2008
solution
Original thoughts provided by Nick at 4:57 PM
Labels: Math Related
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